# Frequent question: What is the electric flux through a sphere of radius?

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Considering a Gaussian surface in the form of a sphere at radius r > R, the electric field has the same magnitude at every point of the surface and is directed outward. The electric flux is then just the electric field times the area of the spherical surface.

## What is the electric flux through a sphere that has a radius?

What is the electric flux through a sphere that has a radius of 1.00 m and carries a charge of +1.00 µC at its centre? Φ = EA E = 8.99 x 109 x 1 x 10-6/ 12 E = 8.99 x 103 N/C. The area that the electric field lines penetrate is the surface area of the sphere of radius 1.00 m.

## Does electric flux depend on radius of sphere?

Gauss’s Law

Point Charge Inside a Spherical Surface: – The flux is independent of the radius R of the sphere.

## What is the electric flux through the spherical Gaussian surface of radius of a?

The electric flux through a spherical Gaussian surface of radius R centered about an amount of charge Q is 1200 Nm2 /C.

## What is flux in sphere?

Considering a Gaussian surface in the form of a sphere at radius r > R , the electric field has the same magnitude at every point of the surface and is directed outward. The electric flux is then just the electric field times the area of the spherical surface.

## How do you calculate electric flux?

Know the formula for electric flux.

1. The Electric Flux through a surface A is equal to the dot product of the electric field and area vectors E and A.
2. The dot product of two vectors is equal to the product of their respective magnitudes multiplied by the cosine of the angle between them.

## How do you calculate total electric flux?

The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux through an area is defined as the electric field multiplied by the area of the surface projected in a plane perpendicular to the field.

## Does electric flux depend on distance?

The magnitude of the electric field everywhere is the same, because the distance from the charge is the same at each point, so we can pull that out of the integral, and we’re left with EA. … The flux doesn’t depend on the distance r.

## What happens to flux when radius is doubled?

Even if the radius is doubled, then the outward electric flux will remain the same as [dfrac{q}{{{varepsilon _0}}}]. This is because the outward electric flux is independent of the distribution of the charges and the separation between them inside the closed surface. Hence, option D is the correct answer.

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## What happens to the flux through the sphere and the magnitude?

What happens to the flux through the sphere and the magnitude of the electric field at the surface of the sphere? The flux and field both increase. … The flux decreases and the field remains the same.

## What is the total flux through the sphere?

Being a scalar quantity, the total flux through the sphere will be equal to the algebraic sum of all these flux i.e. This expression shows that the total flux through the sphere is 1/eO times the charge enclosed (q) in the sphere. The total flux through closed sphere is independent of the radius of sphere .

## What is the electric flux through the Gaussian surface?

According to Gauss’s law, the flux of the electric field →E through any closed surface, also called a Gaussian surface, is equal to the net charge enclosed (qenc) divided by the permittivity of free space (ϵ0): … 4: The electric flux through any closed surface surrounding a point charge q is given by Gauss’s law.